18x^2=12x+5x

Solution for 18x^2=12x+5x equation:

18x^2=12x+5x

We move all terms to the left:

18x^2-(12x+5x)=0

We add all the numbers together, and all the variables

18x^2-(+17x)=0

We get rid of parentheses

18x^2-17x=0

a = 18; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·18·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*18}=\frac{0}{36}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*18}=\frac{34}{36}
=17/18
$